answer:First, we subtract 20 from both sides to get 5x^2 + 19x - 4 > 0. Next, we factor the quadratic to get (5x - 1)(x + 4) > 0. We now have two factors (5x - 1) and (x + 4) that are being multiplied together to give a positive result. For the product of two factors to be positive, either both factors must be positive or both factors must be negative. If 5x - 1 > 0 and x + 4 > 0, then x > frac{1}{5} and x > -4. This means that x > -4. If 5x - 1 < 0 and x + 4 < 0, then x < frac{1}{5} and x < -4. This means that x < frac{1}{5}. So, the integer values of x that do not satisfy the inequality are -3, -2, -1, 0, frac{1}{5}. There are boxed{5} integer values of x that do not satisfy the inequality.The answer is: 5

answer:Let x = 0.overline{009}. Then 1000x = 9.overline{009}, so [1000x - x = 9.overline{009} - 0.overline{009}.]This simplifies to 999x = 9, so x = frac{1}{111}. The product of the numerator and denominator is boxed{111}.The answer is: 111

answer:Squaring both sides of the equation, we get x - 2 = 64. Adding 2 to both sides, we get x = boxed{66}. The answer is: 66

answer:The height of the ball is given by the expression -16t^2+32t+15. To find the maximum height, we need to find the vertex of the parabola. The t-coordinate of the vertex can be found by using the formula t=-frac{b}{2a}, where a and b are the coefficients of the quadratic term and the linear term, respectively. In this case, a=-16 and b=32, so t=-frac{32}{2(-16)}=1. To find the height at the vertex, we substitute t=1 into the expression -16t^2+32t+15. This gives us -16(1)^2+32(1)+15=-16+32+15=31. Therefore, the maximum height of the ball is boxed{31} feet.The answer is: 31