answer:**Answer**: In right triangle ABC, with AB as the hypotenuse, knowing AC and BC allows us to calculate AB. Solution: In right triangle ABC, where angle C = 90^circ, AB is the hypotenuse, thus AB^2 = AC^2 + BC^2, since AC = 3 and BC = 4, then AB = 5, therefore, the correct choice is boxed{C}.

answer:Given that the greatest possible positive integer difference of x and y is 5, we can express this as: y - x = 5 Since x is between 4 and 6, the largest possible value for x that is still less than 6 would be any number that is infinitesimally less than 6, but since we are looking for integer values, we can take x = 5.999... (approaching 6 but not equal to 6). However, since we are looking for the greatest possible positive integer difference, we can consider x = 5 to maximize the difference. Now, we can substitute x = 5 into the equation to find the largest possible value of y: y - 5 = 5 y = 5 + 5 y = 10 Therefore, the largest possible value of y, given that the greatest possible positive integer difference of x and y is 5 and x is between 4 and 6, is y = boxed{10} .

answer:First, you keep 10 percent of the 50 profit for yourself. 10% of 50 = (10/100) * 50 = 5 Now, subtract the amount you keep from the total profit to find out how much is left to distribute among the employees: 50 - 5 = 45 Next, divide the remaining 45 equally among the 9 employees: 45 / 9 employees = 5 per employee So, each employee would get boxed{5} .

answer:To calculate {(sqrt{2023}-1)}^{0}+{(frac{1}{2})}^{-1}, we follow these steps: 1. Any number (except for 0) raised to the power of 0 equals 1. Therefore, {(sqrt{2023}-1)}^{0} = 1. 2. The reciprocal of a fraction is obtained by inverting the fraction. Thus, {(frac{1}{2})}^{-1} = 2. 3. Adding these results together, we get 1 + 2. Combining all the steps, we have: {(sqrt{2023}-1)}^{0}+{(frac{1}{2})}^{-1} = 1 + 2 = boxed{3}.